Help in exception handling in python !

Hey Arnav Goyal

First, you want to take in the input for answer. Then you can raise a ValueError if the answer does not equal yes or no. (Note: we want the ValueError to be caught, so you will want to raise it in the try block.

You will also need to write that conditional differently though because it checks for true false. Think of it in this way. if (answer != "yes") or ("no"). The first one checks if the string "yes" is not the same as answer. This will evaluate to True or False. But checking if "no" will always evaluate to True because a string that is not empty is truthy.

Take a look at this format and see if that works for you!

try: 
    answer = input("Hi {}, do you understand while loops?\n(yes/no)".format(name)).lower()
    if answer != "yes" or answer != "no":
         raise ValueError("""Invalid response. Please use 'yes' or 'no' only!""")

Hope this helps :)

I understand the conditional statement(silly mistake on my part). I didn't know that you could raise an error in the try block itself. I have made the above changes but the code still doesn't work properly.

name = input("What's your name? ")


try: 
    answer = input("Hi {}, do you understand while loops?\n(yes/no)".format(name))
    answer = answer.lower()
    if answer != "yes" or answer!="no":
        raise ValueError("""Invalid response. Please use 'yes' or 'no' only!""")

except ValueError as err:
    print("{}".format(err))
else:
    while answer == "no":
        print("Ok {}, while loops in python repeat as long as a certain boolean condition is met.".format(name))
        answer = input("Hi {}, do you understand while loops?\n(yes/no)".format(name))
        answer = answer.lower()


print("Glad you understood while loops! It was getting repetitive!")

Ah I see. You'll want to make sure that your try/except/else is wrapped in a while loop if you want it to run over and over again :)