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Ksenia Mikhailovskaya
94 PointsHi there! I have troubles with printing out the string:
String firstName = "Ksenia"; console.printf("%s", firstName);
2 Answers
Hunter Dishner
15,086 PointsTheres a couple things that could go wrong. Is console defined correctly? If it isn't or if you want to validate that the %s and variable firstName is set and functioning then try to do a System.out.println("%s", firstName); or something. However, I'm unsure of the "%s" that's only needed when you are printing out a string with a variable inside the string.
Type it like System.out.println(firstName);
You're thinking like System.out.println("My first name is %s", firstName);
If i've missed your question or just didn't understand it myself let me know!
Ralfs Ceksters
6,298 PointsTried your code in the challenge, it passed succesfully.