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Alfredo Prince
6,175 PointsHow is this wrong?
It says that each person should have it's own internal Array. Isn't that what I did?
<?php
//edit this array
$contacts['Alena Holligan'] = ['alena.holligan@teamtreehouse.com'];
$contacts['Dave McFarland'] = ['dave.mcfarland@teamtreehouse.com'];
$contacts['Treasure Porth'] = ['treasure.porth@teamtreehouse.com'];
$contacts['Andrew Chalkley'] = ['andrew.chalkley@teamtreehouse.com'];
echo "<ul>\n";
//$contacts[0] will return 'Alena Holligan' in our simple array of names.
echo "<li>Alena Holligan : alena.holligan@teamtreehouse.com</li>\n";
echo "<li>Dave McFarland : dave.mcfarland@teamtreehouse.com</li>\n";
echo "<li>Treasure Porth : treasure.porth@teamtreehouse.com</li>\n";
echo "<li>Andrew Chalkley : andrew.chalkley@teamtreehouse.com</li>\n";
echo "</ul>\n";
3 Answers
Jason Anello
Courses Plus Student 94,610 PointsHi Alfredo,
I'm not sure if you're on task 1 or 2 but the task 1 instructions state that you should use the "name" key for the name.
Each element of contacts should be another array with the persons name stored in the "name" key.
For Alena and Dave it could look like
$contacts[] = array('name' => 'Alena Holligan');
$contacts[] = array('name' => 'Dave McFarland');
The next task will ask you to add another element to the internal array for the email address.
Let me know if you're still stuck.
piercarlomarinelli
Courses Plus Student 8,207 Points<?php
//edit this array
$contacts = array('Alena Holligan', 'Dave McFarland', 'Treasure Porth', 'Andrew Chalkley');
//the arrays of each contact, must be nested inside the array "father" $contacs
$contacts[0] = ["name" => "Alena Holligan"];
$contacts[1] = ["name" => "Dave McFarland"];
$contacts[2] = ["name" => "Treasure Porth"];
$contacts[3] = ["name" => "Andrew Chalkley"];
echo "<ul>\n";
//$contacts[0] will return 'Alena Holligan' in our simple array of names.
echo "<li>Alena Holligan : alena.holligan@teamtreehouse.com</li>\n";
echo "<li>Dave McFarland : dave.mcfarland@teamtreehouse.com</li>\n";
echo "<li>Treasure Porth : treasure.porth@teamtreehouse.com</li>\n";
echo "<li>Andrew Chalkley : andrew.chalkley@teamtreehouse.com</li>\n";
echo "</ul>\n";
piercarlomarinelli
Courses Plus Student 8,207 Points<?php
//Attention at the syntax, miss "." to concatenate strings and variables.
echo "<li>" $contacts[0]['name'] : $contacts[0]['email']" </li>\n";
echo "<li>" . $contacts[0]['name'] . " : " . $contacts[0]['email'] . "</li>\n";
?>
Mateusz Hyla
11,210 PointsHi. In my opinion it should be like that.
$contacts[] = ["Alena Holligan","alena.holligan@teamtreehouse.com"],[etc]
But I am not quite sure. My main point is that you should create 2 dimensional array like.
$arr[] = [],[],[]
Cheers
Alfredo Prince
6,175 PointsAlfredo Prince
6,175 PointsI'm on task 3 now and I keep getting a syntax error. PHP Parse error: syntax error, unexpected '$contacts' (T_VARIABLE), expecting ',' or ';' in index.php on line 9 Parse error: syntax error, unexpected '$contacts' (T_VARIABLE), expecting ',' or ';' in index.php on line 9 Errors parsing index.php