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Start your free trialJamar Slade
4,244 PointsHow to continue loop after exception?
import random
GREETING = "======> Welcome to Rando <====="
def start_game():
print(GREETING.upper())
answer = random.randint(1,10)
num_of_guess = 1
print(answer)
rules = print("Select an integer between 1 & 10, and I will tell you if it's too high or too low. \n If you can\'t correctly guess my number within 3 tries, it\'s GAMEOVER!")
try:
while num_of_guess < 4:
guess = int(input("Pick an integer between 1 & 10: "))
if 1 < guess > 10:
raise ValueError
#continue
if guess == answer:
print("Congrats! You guessed my number")
else:
if guess > answer:
print('Too High')
else:
print("Too Low")
num_of_guess += 1
except ValueError as err:
print(("Number has to be integer between 1 & 10, try again!"))
start_game()
1 Answer
boi
14,242 PointsPut your try/except
inside the while
loop.
import random
GREETING = "======> Welcome to Rando <====="
def start_game():
print(GREETING.upper())
answer = random.randint(1,10)
num_of_guess = 1
print(answer)
rules = print("Select an integer between 1 & 10, and I will tell you if it's too high or too low. \n If you can\'t correctly guess my number within 3 tries, it\'s GAMEOVER!")
while num_of_guess < 4:
try:
guess = int(input("Pick an integer between 1 & 10: "))
if guess < 1 or guess > 10:
raise ValueError
#continue
if guess == answer:
print("Congrats! You guessed my number")
else:
if guess > answer:
print('Too High')
else:
print("Too Low")
num_of_guess += 1
except ValueError as err:
print(("Number has to be integer between 1 & 10, try again!"))
start_game()
Jamar Slade
4,244 PointsThanks for helping out with this one. I figured it out finally after many many iterations.
Jamar Slade
4,244 PointsJamar Slade
4,244 PointsHaving some issues with my code. Once it raises the ValueError, the program stops. Where I have the "#continue" located is where I thought I had to put the continue for it to run, but that didn't work either.