Welcome to the Treehouse Community
Want to collaborate on code errors? Have bugs you need feedback on? Looking for an extra set of eyes on your latest project? Get support with fellow developers, designers, and programmers of all backgrounds and skill levels here with the Treehouse Community! While you're at it, check out some resources Treehouse students have shared here.
Looking to learn something new?
Treehouse offers a seven day free trial for new students. Get access to thousands of hours of content and join thousands of Treehouse students and alumni in the community today.
Start your free trialEric Nachtsheim
2,006 PointsI am stuck on Challenge 1 of 2 on Multidimensional Music Groups. I'm not sure how to use join/separate here.
Honestly, just not sure how join and separate work with multidimensional lists. Might not understand them well enough in general, and I'm really unsure how to proceed.
musical_groups = [
["Ad Rock", "MCA", "Mike D."],
["John Lennon", "Paul McCartney", "Ringo Starr", "George Harrison"],
["Salt", "Peppa", "Spinderella"],
["Rivers Cuomo", "Patrick Wilson", "Brian Bell", "Scott Shriner"],
["Chuck D.", "Flavor Flav", "Professor Griff", "Khari Winn", "DJ Lord"],
["Axl Rose", "Slash", "Duff McKagan", "Steven Adler"],
["Run", "DMC", "Jam Master Jay"],
]
# Your code here
for groups in musical_groups:
for member in groups:
print(member.join(", "))
3 Answers
Peter Vann
36,427 PointsHi Eric!
It looks like you were trying to use more of a JavaScript type of syntax and you had one loop too many.
This passes the first task:
musical_groups = [
["Ad Rock", "MCA", "Mike D."],
["John Lennon", "Paul McCartney", "Ringo Starr", "George Harrison"],
["Salt", "Peppa", "Spinderella"],
["Rivers Cuomo", "Patrick Wilson", "Brian Bell", "Scott Shriner"],
["Chuck D.", "Flavor Flav", "Professor Griff", "Khari Winn", "DJ Lord"],
["Axl Rose", "Slash", "Duff McKagan", "Steven Adler"],
["Run", "DMC", "Jam Master Jay"],
]
# Your code here
for members in musical_groups:
print( ", ".join(members) )
More info:
https://www.w3schools.com/python/ref_string_join.asp
This passes the second task:
musical_groups = [
["Ad Rock", "MCA", "Mike D."],
["John Lennon", "Paul McCartney", "Ringo Starr", "George Harrison"],
["Salt", "Peppa", "Spinderella"],
["Rivers Cuomo", "Patrick Wilson", "Brian Bell", "Scott Shriner"],
["Chuck D.", "Flavor Flav", "Professor Griff", "Khari Winn", "DJ Lord"],
["Axl Rose", "Slash", "Duff McKagan", "Steven Adler"],
["Run", "DMC", "Jam Master Jay"],
]
# Your code here
for members in musical_groups:
if len(members) == 3:
print( ", ".join(members) )
More info:
https://www.tutorialspoint.com/python/list_len.htm
https://www.tutorialspoint.com/python/tuple_len.htm
I hope that helps.
Stay safe and happy coding!
Eric Nachtsheim
2,006 PointsI see. Let me make sure I have this right. print( ", ".join(members) ) What this does is join every item in the inner lists (is that the right terminology? Not sure) together as a string. Then each string is looped through, printing each one in its own line. Is that in the ballpark?
In any case, thank you so much for your help. I really appreciate it.
Peter Vann
36,427 PointsYes - you are in the ballpark.
This is the output for the second task:
Ad Rock, MCA, Mike D.
Salt, Peppa, Spinderella
Run, DMC, Jam Master Jay
Again, I hope that helps.
Stay safe and happy coding!