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Java Java Basics Perfecting the Prototype String Equality

I cannot think of any other method to write this out.

// I have imported a java.io.Console for you, it is named console. String firstExample = "hello"; String secondExample = "hello"; if (firstExample.equals("s%, secondExample")){ console.printf("first is equal to second \n\n"); System.exit(0); } String thirdExample = "HELLO";

Why is this not correct?

Equality.java
// I have imported a java.io.Console for you, it is named console. 
String firstExample = "hello";
String secondExample = "hello";
if (firstExample.equals("s%, secondExample")){
  console.printf("first is equal to second \n\n");
  System.exit(0);
}
String thirdExample = "HELLO";

2 Answers

This line if (firstExample.equals("s%, secondExample")) should be if( firstExample.equals(secondExample))

Seth Kroger
Seth Kroger
56,413 Points

Further, you should remove the line System.exit(0);