Welcome to the Treehouse Community
Want to collaborate on code errors? Have bugs you need feedback on? Looking for an extra set of eyes on your latest project? Get support with fellow developers, designers, and programmers of all backgrounds and skill levels here with the Treehouse Community! While you're at it, check out some resources Treehouse students have shared here.
Looking to learn something new?
Treehouse offers a seven day free trial for new students. Get access to thousands of hours of content and join thousands of Treehouse students and alumni in the community today.
Start your free trialLeah Kelly
4,141 PointsI can't figure out how to do this.
Write a function named minutes that takes two datetimes and, using timedelta.total_seconds() to get the number of seconds, returns the number of minutes, rounded, between them. The first will always be older and the second newer. You'll need to subtract the first from the second.
Is there any way to simplify this?
1 Answer
Steven Parker
231,236 PointsPerhaps it would help to break it down into steps:
- subtract the older time (first argument) from the newer one (second argument)
- doing math on datetimes gives you a timedelta (no special conversion needed)
- use the total_seconds() method to get the number of seconds from the timedelta
- use math to convert seconds into minutes
- finally, round to the nearest whole minute