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Java Java Basics Getting Started with Java Strings, Variables, and Formatting

Trushit Patel
Trushit Patel
477 Points
Posted by Trushit Patel
Trushit Patel
477 Points

I can't make out my mistake -

Please help me with this. I don't see any error in this.

Name.java 
String firstName = "Trushit" ;
console.printf("%s",firstName);// I have setup a java.io.Console object for you named console

2 Answers

Kourosh Raeen
Kourosh Raeen
23,733 Points
Kourosh Raeen
Kourosh Raeen
23,733 Points

The problem is you're not printing what the instruction is asking you:

// I have setup a java.io.Console object for you named console
String firstName = "Trushit";
console.printf("%s can code in Java!", firstName);
Unsubscribed User
Unsubscribed User
7,176 Points
Unsubscribed User
Unsubscribed User
7,176 Points

Hi Trushit,

you just made a small mistake in your code: There is space between "Trushit" and the semicolon. Just delete the space and the program will run :)

String firstName = "Trushit";
console.printf("%s",firstName);

I hope that was helpful, Patrick