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C# C# Objects Inheritance Throwing Exceptions

Jeongeui Ji
Jeongeui Ji
3,761 Points
Posted by Jeongeui Ji
Jeongeui Ji
3,761 Points

I do not understand... Please help me.

I think I coded the right condition of the if statement as not to be less than 0 or greater than 20. And then I threw an exception afterwards. Did i do something wrong? Thanks in advance.

Program.cs 
int value = int.Parse(Console.ReadLine());

Console.WriteLine(string.Format("You entered {0}",value));

if(!value < 0 || value >20)
{
    throw new System.Exception();
}
Kevin Agpaoa
Kevin Agpaoa
10,503 Points
Kevin Agpaoa
Kevin Agpaoa
10,503 Points

!value < 0 is the same as value > 0. To correct the problem you can do value < 0 or !(value >0), so values 1-19 will be excluded from the exception.

1 Answer

andrewgabriel
andrewgabriel
18,106 Points
andrewgabriel
andrewgabriel
18,106 Points

I would just add () around value < 0 and leave ! outside so that way it evaluates the whole statement. Before that you were modifying value to false since you didn't include < 0 within that !(). So it should look like this:

int value = int.Parse(Console.ReadLine());

Console.WriteLine(string.Format("You entered {0}",value));

if(!(value < 0) || (value >20))
{
    throw new System.Exception();
}

Interesting question!