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Java Java Basics Getting Started with Java IO

Posted by anthonybeckles
anthonybeckles
2,065 Points

I honestly have no idea what I have done wrong. Can someone help?

Don't know maybe I am just tired and can't see what I have done wrong.

IO.java 
// I have imported java.io.Console for you.  It is a variable called console.
String firstName = console.readLine("What is your name?  ");
String lastName = console.readLine("What is your name?  ");
console.printf ("Hello, my name is %s/n" , firstName);

3 Answers

ISAIAH S
ISAIAH S
1,409 Points
IO.java 
// I have imported java.io.Console for you.  It is a variable called console.

// This will ask: 'Enter your first name: '
String firstName = console.readLine("Enter your first name:  ");

// This will ask: 'Enter your last name: '
String lastName = console.readLine("Enter your last name:  ");


// This will say: 'First name: <WHAT_YOU_ENTERED_IN_THE_FIRSTNAME_VARIABLE>'
console.printf("\nFirst name: %s\n", firstName);

// This will say: 'Last name: <WHAT_YOU_ENTERED_IN_THE_LASTNAME_VARIABLE>'
console.printf("Last name: %s", lastName);

// So together this will say:
// 'Enter your first name: 
// Enter your last name: 
// 
// 
// First name: 
// Last name: '

Make sense?

ISAIAH S

anthonybeckles
anthonybeckles
2,065 Points

Yeah I understand it all thanks :)

Dan Johnson
Dan Johnson
40,533 Points
Dan Johnson
Dan Johnson
40,533 Points

It just wants the format string to be "First name: %s" exactly.

Edit: Won't be used for this String, but the escape character is a backslash, so if you wanted a newline it would be "\n".

anthonybeckles
anthonybeckles
2,065 Points
anthonybeckles
anthonybeckles
2,065 Points

Oh woow (facepalm) It's amazing I even got this far if I can't do that. Thanks anyway.