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Robert Bienkowski
183 PointsIm not understanding what it's asking?
it says to Now replace <YOUR NAME> in the console.printf expression with the firstName variable using the string formatter. I have no clue what that means. I dont know what a string formatter is. They pretty much blew threw the video without talking about it
// I have setup a java.io.Console object for you named console
String firstName = "Robbo";
console.printf("<firstName> can code in java!\n");
1 Answer
Seth Kroger
56,413 Pointsprintf() allows you to put placeholders in the string for other variables that are also passed into printf after the string. These placeholders start with a percent sign (%) and have their own special syntax. You don't need to worry about all the details just yet, just that %s means "substitute a string". The placeholders will be substituted in order, with the first substituted with the first variable that follows, etc. So to insert the variable firstName into the output your you write:
console.printf("%s can code in java!\n", firstName);
Robert Bienkowski
183 PointsRobert Bienkowski
183 Pointsconsole.printf("Hello, my name is %s\n", firstName);
This was how we wrote in the beginning. So i was confused and did not realize that works in general. I thought it had to be in that format. Thanks Seth!