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Cross Ender
9,567 PointsI'm simplicitly stuck here.
.
from models import Challenge
def create_challenge(name, language, steps=1):
Challenge.create(name=name,
language=language,
steps=steps)
def search_challenges(name, languge):
return Challenge.where(Challenge.name.contains(name)
Ken LaRose
Python Web Development Techdegree Student 21,982 PointsI am also stuck on this code challenge. I believe there are some syntax errors in your search_challenges function. But, then again, my function isn't working either.... check out the peewee documentation here: http://docs.peewee-orm.com/en/latest/peewee/querying.html#filtering-records
This is what I wrote:
def search_challenges(name, language):
challenges = Challenge.select().where(Challenge.name == name,
Challenge.language == language)
return challenges
if I figure it out, I'll post a follow-up comment
2 Answers
Christopher Shaw
Python Web Development Techdegree Graduate 58,248 PointsThere are a few hints in the question, i.e, it asks for equal and says use the == as well as put both arguments in the where()
Ken LaRose
Python Web Development Techdegree Student 21,982 Pointsokay... I figured it out. The query I posted in the comments above failed because it was searching for an exact match on name instead of using contains(). That's not your issue though. Basically you'll just want to insert the select() method between Challenge and where(), like Challenge.select().where(blah, blah). You're on the right track!
nicole lumpkin
Courses Plus Student 5,328 Pointsnicole lumpkin
Courses Plus Student 5,328 PointsHey Sarah, I'd love to help but you're ahead of me in the materials :) I did however search the title of the challenge in the community and the second post I can across detailed an explanation as well as the solution. Perhaps you could work backwards and figure out where things went wrong. Search phrase: CRUD Search Function