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Java Java Basics Getting Started with Java Strings, Variables, and Formatting

Posted by Juan Losauro
Juan Losauro
783 Points

I'm stuck,

As you may see, I'm declaring a String variable and naming it "Juan" but as I print it, the exercise fails.

Name.java 
// I have setup a java.io.Console object for you named console

String fistName = "Juan";

console.printf(fistName + "can code in Java!");
Juan Losauro
Juan Losauro
783 Points

Oh wait I wrote fistName, sorry

2 Answers

Mohammed AlShaiban
Mohammed AlShaiban
6,455 Points

The problem here is in your print statement, you need to add %s for the string to be printed. 

console.printf("%s can code in Java!", firstName);

If you were using println instead of printf then your print statement would be correct.

Juan Losauro
Juan Losauro
783 Points
Juan Losauro
Juan Losauro
783 Points

I've already noticed it! Thanks for the help mate!