I'm stumped with this... can anyone help? Thanks!

Question

I've been able to get this far in the course, but can't get past this step. Can anyone please offer some help.... thanks!

ScrabblePlayer.java

public class ScrabblePlayer {
  // A String representing all of the tiles that this player has
  private String tiles;

  public ScrabblePlayer() {
    tiles = "";
  }

  public String getTiles() {
    return tiles;
  }

  public void addTile(char tile) {
    tiles += tile;
  }

  public boolean hasTile(char tile) {
    return tiles.indexOf(tile) != -1;
  }
}

Example.java

// This code is here for example purposes only
public class Example {

  public static void main(String[] args) {
    ScrabblePlayer player1 = new ScrabblePlayer();
    player1.addTile('d');
    player1.addTile('d');
    player1.addTile('p');
    player1.addTile('e');
    player1.addTile('l');
    player1.addTile('u');

    ScrabblePlayer player2 = new ScrabblePlayer();
    player2.addTile('z');
    player2.addTile('z');
    player2.addTile('y');
    player2.addTile('f');
    player2.addTile('u');
    player2.addTile('z');

    int count = 0;
    // This would set count to 1 because player1 has 1 'p' tile in her collection of tiles
    count = player1.getCountOfLetter('p');
    // This would set count to 2 because player1 has 2 'd'' tiles in her collection of tiles
    count = player1.getCountOfLetter('d');
    // This would set 0, because there isn't an 'a' tile in player1's tiles
    count = player1.getCountOfLetter('a');

    // This will return 3 because player2 has 3 'z' tiles in his collection of tiles
    count = player2.getCountOfLetter('z');
    // This will return 1 because player2 has 1 'f' tiles in his collection of tiles
    count = player2.getCountOfLetter('f');
  }
}

Answer 1 · 2017-05-20T21:38:53Z

May 20, 2017 9:38pm

Hey Charlie,

You'll need the following to complete this challenge:

public int getCountOfLetter(char letter) { 
    int count = 0; 
    for(char tile : tiles.toCharArray()) {
      if (tile == letter) {
        count ++; 
      } 
    }

    return count;
  }

So, the challenge 2/2:

You'll need to use your skills to loop through each of the tiles, use an equality check, and then increment a counter if the tile and letter match. You got this!

You want to use a For Each loop, we use;

for(char tile : tiles.toCharArray()) {
}

The above line means, for every tile (user passes in) in tiles. We use the toCharArray() method, this basically splits up the String into a character array (chars) allowing the loop to check each tile in tiles.

Then we implement an if statement (equality check) to see if the tile is equal to the letter, if it is the counter will increment, if it's not it will just return the current count.

 if (tile == letter) {
        count ++; 
      }

Once we do that we return the count.

Hope this makes sense!

Welcome to the Treehouse Community

Looking to learn something new?

Charlie Flowers

Charlie Flowers

I'm stumped with this... can anyone help? Thanks!

1 Answer

Gabe Olesen

Gabe Olesen

Charlie Flowers

Charlie Flowers