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Sergio Lopez
13,088 Pointsinvalid keyword argument
If this were pseudocode, it would work, but I get the 'invalid keyword argument" inside the timedelta function when I try to pass the string variable as an argument. How do you pass the string argument to the timedelta function?
import datetime
starter = datetime.datetime(2015, 10, 21, 16, 29)
integer = 5
string = "hours"
def time_machine(integer, string):
return starter + datetime.timedelta(string = integer)
# Remember, you can't set "years" on a timedelta!
# Consider a year to be 365 days.
## Example
# time_machine(5, "minutes") => datetime(2015, 10, 21, 16, 34)
2 Answers
Tree Casiano
16,436 PointsHi Sergio, I built the code for this challenge out of a series of if-else statements. Here's the first snippet of code from my function. Using the name of the variable in your case "string," throws a keyword error because the function requires one of the datetime keywords such as hours, days, or minutes rather than a variable that stores the value for the particular number of hours, days, etc.
def time_machine(integer, string1):
if string1 == 'hours':
return starter + datetime.timedelta(hours=integer)
Kenneth Love
Treehouse Guest TeacherIf this were pseudocode, it would work
Well, yeah :) that's the beauty of pseudocode, it always does what you expect.
Tree Casiano's suggestion is a good one.