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Python

Invalid Syntax for an Exception, Please Help

I am getting a SyntaxError for line two where I am trying to create an exception. I want to create this exception because a user might enter "two" instead of "2" which breaks my program. Please advise on why I am getting this error. Thank you!

number=int(input("Please pick a number. "))
except ValueError:
    print("Please pick an integer.")
if number < 100:
    print("{} is less than 100!".format(number))
if number > 100:
    print("{} is greater than 100!".format(number))
if number == 100:
    print("{} equals 100!".format(number))

elif number == 200:
    print("{} is the magic number!".format(number)) 

1 Answer

Steven Parker
Steven Parker
231,007 Points

If you want to catch errors, you need a "try" block before your "except". Take a look at the examples on the documentation pages that cover handling exceptions.

Thank you for your advise! I found it very helpful reading the documents.