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Start your free trialMytech T
Full Stack JavaScript Techdegree Student 1,427 PointsIs this solution acceptable?
check this solution, please.
const random = (upper, lower) => typeof(upper,lower) === 'number' ? Math.floor(Math.random() * (upper - lower + 1)) + lower : `That's not a number`
console.log(random(20, 10))
4 Answers
Steven Parker
231,261 PointsYou can only use "typeof" on one thing at a time.
If I try "console.log(random(20, "Joe"))
" I get "That's not a number
"
But if I try "console.log(random("Joe", 10))
" I just get "NaN
"
Mytech T
Full Stack JavaScript Techdegree Student 1,427 PointsSteven Parker, but it worked, try it on the console?
Steven Parker
231,261 PointsSee the examples added to my answer.
Mytech T
Full Stack JavaScript Techdegree Student 1,427 PointsSteven Parker, Yep, you rightπ
Joseph Lander
Full Stack JavaScript Techdegree Graduate 27,765 PointsI think this is interesting as to the difference between isNaN() and typeof X === 'number'. [I figure they must be different or why would both exist?]
I wrote a similar logic with typeof before watching the solution. To explore the difference I changed my upper number check to isNaN and ran the following code:
const randomNumber = (lower, upper) => {
if (typeof lower !== 'number' || isNaN(upper)) {
throw Error('parameters are not both numbers');
}
return Math.floor(Math.random() * (upper - lower + 1)) + lower;
};
console.log(randomNumber(2, '4')); // 4 as a string is coerced/considered a number
console.log(randomNumber('two', 4)); // 'two' does NOT get coerced/considered a number - throws error
Joseph Lander
Full Stack JavaScript Techdegree Graduate 27,765 PointsPS Like your use of a ternary Mytech T. More concise than mine.