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Java Java Basics Perfecting the Prototype String Equality

artur kowalski
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.a{fill-rule:evenodd;}techdegree
artur kowalski
Front End Web Development Techdegree Student 1,666 Points
Posted by artur kowalski
.a{fill-rule:evenodd;}techdegree
artur kowalski
Front End Web Development Techdegree Student 1,666 Points

JAVA Basic

Add another if statement that checks if the firstExample is equal ignoring case to thirdExample. If it, is print out "first and third are the same ignoring case".

I have error in my code and cant figurate by myself. Could you write code so I can see where I did mistake.? Thank you Artur

Equality.java 
// I have imported a java.io.Console for you, it is named console. 
String firstExample = "hello";
String secondExample = "hello";
String thirdExample = "HELLO";

if (firstExample == secondExample){

console.printf("First is equal to second");
} 

if (firstExample.equalslgnoreCase("thirdExample")) {

  console.printf("first and third are the same ignoring case");
}

2 Answers

Ronaldo Cristiano
Ronaldo Cristiano
488 Points
Ronaldo Cristiano
Ronaldo Cristiano
488 Points 
String firstExample = "hello";
String secondExample = "hello";
String thirdExample = "HELLO";

if(firstExample.equals(secondExample)){
 console.printf("first is equal to second");
}

if(firstExample.equalsIgnoreCase(thirdExample)){
 console.printf("first and third are the same ignoring case");
}
Daniel Clarck
Daniel Clarck
325 Points
Daniel Clarck
Daniel Clarck
325 Points

Hello, you can't write String == String, you have to write String.eqaulsIngnoreCase(String).