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Michelle Mangwiro
Courses Plus Student 467 PointsJava Basics- Your name task
I don't understand where I am going wrong on my last line
firstName = ("Michelle");
String firstName = "Michelle";
console.printf("%s can code in Java!,firstName");
3 Answers
Justin Kraft
26,327 PointsClose the string with a double quote followed by a comma, then the variable name.
console.printf("%s can code in Java!", firstname);
Michelle Mangwiro
Courses Plus Student 467 Pointskk cheers
Grigorij Schleifer
10,365 PointsHi Michelle,
just few modifications.
Task one:
// declare a String variable and initialize (= sign) it to your name
String firstName = "Michelle";
Task two:
// use the console.printf method to write "Michelle can code in Java"
// console is a name of the Console class that has the method printf()
console.printf("Michelle can code in Java");
Task three:
// replace Michelle with %s, this is the required String formatter
// to use the formatter place it where you want your name should be and after " " (not inside) write ("%s some text " , firstName)
console.printf("%s can code in Java", firstName);
I hope I could help you
Grigorij
Michelle Mangwiro
Courses Plus Student 467 PointsThank you
Grigorij Schleifer
10,365 PointsHi Michelle,
can you mark an answer as best? So other could see this post as solved.
Grigorij