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javier montoya
51 PointsJava Console printf
Its asking for me to put in the code for the first name and i did and even watched the video again but i keep getting an error
String firstName= console.readLine("javier");
String lastName= console.readLine("montoya");
console.printf=("First name");
2 Answers
Lukas Baumgartner
14,817 PointsI think the task is to print out a Name you entered when prompted by the program. It should look something like this:
String firstName = console.readLine("Enter your first name: ");
String lastName = console.readLine("Enter your last name: ");
console.printf = ("First Name: %s %n Last Name %s %n",firstName, lastName);
So. What did I do here? The first two lines read the userinput. The user has to input his first an last name into the console. This input is then stored in the variables firstName and lastName. the third line is where we concat the string and put it out in the console to read. %s is a placeholder for the variables we want to show. You have to be carefull to place the variables in the correct order after the quotationmarks! %n is a formatting tool. Just try it out to see what it does ;)
I hope this makes it clearer now!
Christopher Lebbano
15,338 PointsTry using no quotation marks and using firstName instead of Firstname