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Thomas Branch
1,178 PointsJava quiz parser broken
I am doing the last quiz on the first section of the java track. There is no way to satisfy the quizzes third task. I can't see an error in this code.
String firstName = ""; String lastName = ""; console.readLine("first name", firstName); console.readLine("last name", lastName); console.printf('first name: %s', firstName);
However, the interpreter gives me a "bummer". I've played around with formatting between double quotes and single quotes, the ordering of the lines, etc. All with the same result.
// I have imported java.io.Console for you. It is a variable called console.
String firstName = "";
String lastName = "";
console.readLine("first name", firstName);
console.readLine("last name", lastName);
console.printf('first name: %s', firstName);
3 Answers
Craig Dennis
Treehouse TeacherHey Daniel,
In Java single quotes and double quotes make a difference.
console.printf('first name: %s', firstName);
Single quotes are used to represent a char literal like this:
char letter = 'A';
String letters = "A";
They are different, we get into it in the next course, Java Objects. I should add a check assuming that error was a bit mind-blowing ;) Sorry for the frustration.
Mikkel Rasmussen
31,772 PointsIt shoud be
// I have imported java.io.Console for you. It is a variable called console.
String firstName = console.readLine("Enter your first name: ");
String lastName = console.readLine("Enter your last name: ");
console.printf("First name: %s", firstName);
console.printf("Last name: %s", lastName);
Thomas Branch
1,178 PointsHmmm, both should work. I passed tasks 1 & 2 with the readLines & string definitions as you see them.
Thanks for the fast response.