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Java Java Basics Getting Started with Java Strings, Variables, and Formatting

AYMERIC FIGEROU
AYMERIC FIGEROU
3,748 Points
Posted by AYMERIC FIGEROU
AYMERIC FIGEROU
3,748 Points

java.util.MissingFormatArgumentException: Format specifier '%s' ()

Hello TreeHouse Com,

Quite don't get it why there is a message error. My variable has been declared, following by the string formatter %s. It sounds good. or?

Name.java 
// I have setup a java.io.Console object for you named console
String firstName="Jaean";
console.printf("%s");
console.printf(" can code in Java");

2 Answers

Christopher Augg
Christopher Augg
21,223 Points
Christopher Augg
Christopher Augg
21,223 Points

Aymeric,

You should only use one console.printf(). On task 3/3 you are supposed to just alter it to use %s. When formatting a string that includes a variable we do the following:

       String titleOfMovie = "The Shawshank Redemption";
       console.printf("I really enjoyed watching %s", titleOfMovie);

So how would you do it for the challenge?

Hope this helps.

Regards,

Chris

AYMERIC FIGEROU
AYMERIC FIGEROU
3,748 Points
AYMERIC FIGEROU
AYMERIC FIGEROU
3,748 Points

It does indeed. I didn't understand i had to respecify it. If i can say so.

Thanks you