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Python Django Class-based Views Classy Views Basic View

My challenge is not passing. any tips?

I don´t know why it doesn´t find the URL...

myproject/urls.py
from django.conf.urls import url, include

from . import views

urlpatterns = [(r'^$', views.WelcomeView.as_view(), name="WelcomeView"),]
myproject/views.py
from django.views.generic import View
from django.http import HttpResponse

class WelcomeView(View):
    def get(self, request):
        return HttpResponse("Hello Mate")

any patterns for url patterns need to look like url()

1 Answer

Christopher Gunawan
Christopher Gunawan
10,754 Points
urlpatterns = [url(r'^$', views.WelcomeView.as_view(), name="WelcomeView"),]

You forgot to place 'url'.