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Posted February 2, 2020 8:31am by

my loop exits on 4th name I when put '' <=3'' , and i dont know how to get the players to print according to the spec

my loop exits on 4th name I when put ''' <=3''' why does it do that? I don't know how to get the players to print according to the specifications of the challenge i.e to get the names assigned to numbers starting from 1 and then choose a player to be goalie by their assigned number. here's my code:

players_name = []
# TODO Create an empty list to maintain the player names
# TODO Ask the user if they'd like to add players to the list.
while len(players_name) <=3:

    add_players = input("would you like to add players to the list? Y/N  " )
    if add_players.lower() == "y":
        players_nom = input("please enter players name? ")
        players_name.append(players_nom)

else:

    print (*players_name, sep='\n')

    goalie = input(" please select goalie from the list")

    print("The goalie {} ".format(goalie))     ```

February 2, 2020 8:36am

Steven Parker or anyone else who is willing to help (thank you) I can't seem to read this code, its confusing.

count = 1
for i in players:
    print("Player{}: {}".format(count, i))
    count +=1 ```

February 2, 2020 8:41am

Steven Parker or anyone else who is willing to help (thank you).

and this has an input with yes and no, it is not followed up with an if statement. how does it work without an if statement? What does the break function do on line 11?:

players = []
# TODO Ask the user if they'd like to add players to the list.
add_player = str.lower(input("Would you like to add a player to the list? \n(Yes/No) "))
player_name = input("What's the player's name? ")
players.append(player_name)
# If the user answers "Yes", let them type in a name and add it to the list.
while len(players) <= 3:
    more_players = str.lower(input("Would you like to add another player? \n(Yes/No) "))
    if more_players == "no":
        break
    player_name = input("What's the player's name? ")
    players.append(player_name)
# If the user answers "No", print out the team 'roster'
# TODO print the number of players on the team
print("There are", len(players), "players on the team.")  ```

1 Answer

February 2, 2020 11:40am

Using "while len(players_name) <=3:" as the loop sets the condition that the loop should only run while the list has 3 or less items in it. So it will always stop after taking a 4th player. If that's not your intention you may need a different conditional test.

Here's your 2nd item with comments added:

count = 1                                   # start the player count with 1
for i in players:                           # let "i" represent each player name in turn
    print("Player{}: {}".format(count, i))  # print the count followed by the player's name
    count +=1                               # add 1 to the count before going to the next player

And for your 3rd item, the input is followed up by this "if" statement if more_players == "no"
It works by only doing the "break" when the answer was "no". And a "break" causes a loop to end.

February 2, 2020 8:29pm

Hi Steven Parker, my code kind of works, the only bit that doesn't work full is the roaster bit for the players. BTW if you are to test my code, it allows me to enter four names then it exits. I specified in the code for 3 or less then 3 names but when i run the code it allows me to enter 4 names. If i am to get the second bit right you mean:

player_nom = 1 
for player_name in player_nom
    print("player {}: {}".fomat(count, player_nom))
    player_nom +=1```

February 2, 2020 10:57pm

Your limit of "3 or less" is for taking on another player. So when you have 3, it allows a 4th; but when you have 4 it stops. If you only want to allow 3 players, use "< 3" instead of "<= 3".

And your refactoring of the 2nd item changes the names inconsistently so it won't work. You can certainly use any names you like, but you must change each name in every location where it is referenced.

February 3, 2020 9:52am

Steven Parker or anyone else kindly willing to help. I couldn't quite get the second item right so i watched the solution video, and recreated it and line 20 is not function correctly. sometimes it prints out a random letter other time it prints out a letter in relation to the number and character position of the name. the file is team2.py. https://w.trhou.se/9s6ijgtncy

February 3, 2020 5:11pm

At first glance, the code on line 14 stands out:

for players_name in players_name:

You should use a different variable for the individual player than the one used for the entire list of players.

February 3, 2020 5:26pm

thanks Steven Parker, i don't why this challenge popped up if i wasn't taught or shown something. I watched the Iteration video for lists and its all been explained.

February 3, 2020 5:54pm

mohan Abdul — good deal. You can mark the question solved by choosing a "best answer".
And happy coding!

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