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Python Django Basics Final Details Article detail view

Nathan Magyar
Nathan Magyar
6,670 Points
Posted by Nathan Magyar
Nathan Magyar
6,670 Points

Our view needs an URL. Add a new url to article/urls.py. The pattern should be "article/" and then the pk argument, whic

I'm getting an error reminding me to make sure that the "articles/article_details.html" template is being used. This question seems to be asking for the same setup as the writer_details view and url, which I've essentially copied over. What am I missing?

articles/views.py 
from django.shortcuts import render

from .models import Article, Writer


def article_list(request):
    articles = Article.objects.all()
    return render(request, 'articles/article_list.html', {'articles': articles})


def writer_detail(request, pk):
    writer = Writer.objects.get(pk=pk)
    return render(request, 'articles/writer_detail.html', {'writer': writer})

def article_detail(request, pk):
    article = Article.objects.get(pk=pk)
    return render(request, 'articles/article_detail.html', {'article': article})
articles/urls.py 
from django.conf.urls import url

from . import views

urlpatterns = [
    url(r'writer/(?P<pk>\d+)/$', views.writer_detail),
    url(r'', views.article_list),
    url(r'article/(?P<pk>\d+)/$', views.article_detail),
]

1 Answer

Ryan S
Ryan S
27,276 Points
Ryan S
Ryan S
27,276 Points

Hi Nathan,

Your url pattern is correct, but you have to be careful of where you place it in the list. Because Django checks each pattern in order, you want to put more complex patterns towards the beginning of the list, otherwise, a simpler pattern could be matched first if they have a portion of the regex in common..

Just move your article_detail pattern before the article_list and it should pass.

Nathan Magyar
Nathan Magyar
6,670 Points
Nathan Magyar
Nathan Magyar
6,670 Points

I see. That worked! Thank you!