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Start your free trialKhatia Bagaturia
2,050 PointsPlease tell me what Am I doing Wrong In this Task ?
<!DOCTYPE html>
<html>
<head>
<title>Lake Tahoe</title>
<link rel="stylesheet" href="page.css">
<link rel="stylesheet" href="style.css">
</head>
<body>
<header id="top" class="main-header">
<span class="title">Journey Through the Sierra Nevada Mountains</span>
<h1>Lake Tahoe, California</h1>
</header>
<div class="primary-content t-border">
<p class= "intro"> </p>
Lake Tahoe is one of the most <span>breathtaking attractions</span> located in California. It's home to a number of ski resorts, summer outdoor recreation, and tourist attractions. Snow and skiing are a significant part of the area's reputation.
</p>
<a href="#more">Find out more</a>
</div>
<footer class="main-footer">
<p>All rights reserved to the state of <a href="#">California</a>.</p>
<a href="#top">Back to top »</a>
</footer>
</body>
</html>
.intro {
font-size: 1.25em;
line-height: 2;
}
2 Answers
Steven Parker
231,236 PointsWhen you added the class to the paragraph tag, it looks like you also added an extra closing tag (ending the paragraph prematurely).
Also, line-height is by nature a multiplier, so you should use the value asked for in the instructions unchanged.
Heidi Fryzell
Front End Web Development Treehouse Moderator 25,178 PointsHello Khatia,
The issue is with the line height. It is a little bit tricky because in the previous task you had to calculate the font-size. So when you get to the line-height, you are probably thinking you have to calculate that as well.
Re-read the directions: Next, give intro a unitless line-height that's 1.6 times larger than the font-size value.
They are asking for a "unitless" line-height. So you can just plug in 1.6. No calculation necessary. It literally means 1.6 x the normal line height.
.intro {
font-size: 1.25em;
line-height: 1.6;
}
I hope that helps. Happy coding!
Heidi