Print out to the screen using the printf method on console, "First name: " and the user's first name.

Hi James,

Your code is very nearly correct - the 3rd line doesn't need the quotes around console.printf. The quotes indicate a literal string value so the contents won't be interpreted as instructions. You will also need the text "First name: " as part of what you output to the screen. This gives you:

String firstName = console.readLine("firstName");
String lastName = console.readLine("lastName");
console.printf("First name: %s",firstName);

This should work just fine. Adding the last name part should be just the same format.

This isn't an error at all, but just so you are aware - where you used the readLine methods, in the quotes you have used firstName and lastName, just like the variables name themselves. This text in quotes doesn't have to be the same as your variables names - this is what will be displayed to the user as the on screen prompt when asking for input.

So for example, on the course, they use something like:

String firstName = console.readLine("What is your first name?  ");

With the 2 spaces at the end of the question, so that the text the user types will be away from the end of the sentence, and is a little more pleasing to the eye.

I hope this helps, but shout if not :)

Thanks, Rich

I appreciate the great response! Thank you for taking time out of your day to help me out! Have a good one!!