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Start your free trialMar Bocatcat
7,405 PointsRe.Expressions
What am i missing here? Any advice?
import re
string = '1234567890'
def good_numbers(string):
return re.findall(r'[\w\d][^567]', string, re.I)
1 Answer
Chris Freeman
Treehouse Moderator 68,441 PointsHi Mar,
There are two issues with your solution. First, the task asks only to create a variable named good_numbers
, not a function.
Second, your regex is overly complicated for the task. By combining two character sets your regex r'[\w\d][^567]'
says:
`[any word or decimal character][not followed by 5 6 or 7]' this means the "7" will still be found "good" because it is follow by "8".
Your regex need only say `[not a 5, 6 or 7]'. This can be accomplished using:
good_numbers = re.findall(r'[^567]', string)
The re.I
is not needed since there is no character case to ignore.
Best of luck. Keep Coding!
Mar Bocatcat
7,405 PointsMar Bocatcat
7,405 PointsThank you ! I need to read the details more!