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Java Java Basics Getting Started with Java Strings, Variables, and Formatting

Posted by Filipe Couto
.a{fill-rule:evenodd;}techdegree
Filipe Couto
Full Stack JavaScript Techdegree Student 2,521 Points

replace firstName variable using the string formatter.

cant see whats wrong with my code

Name.java 
// I have setup a java.io.Console object for you named console
String firstName ="Filipe";
console.printf ("%s can code in Java",firstname);

1 Answer

Jason Anders
MOD
Jason Anders
Treehouse Moderator 145,860 Points
Jason Anders
Jason Anders
Treehouse Moderator 145,860 Points

Hey there Filipe,

You misspelled the firstName variable in the printf() statement. The original variable has an upper-cased 'N.'

Keep Coding! :dizzy:

Filipe Couto
.a{fill-rule:evenodd;}techdegree
Filipe Couto
Full Stack JavaScript Techdegree Student 2,521 Points

tks for the reply ,

i try both 'n' and 'N'

String firstName ="Filipe"; console.printf ("%s can code in Java",firstname);

or String firstName ="Filipe"; console.printf ("%s can code in Java",firstName);