Stuck at datetime.datetime

Question

Would someone be able to help me understand how to answer this question? I think im suppose to use strs/strp to convert the string to a time. But i am not sure how/what method to use.

Any help is appreciated! Thanks!

time_machine.py

import datetime

starter = datetime.datetime(2015, 10, 21, 16, 29)

# Remember, you can't set "years" on a timedelta!
# Consider a year to be 365 days.

## Example
# time_machine(5, "minutes") => datetime(2015, 10, 21, 16, 34)

def time_machine(ints, strs):
  strs 
  time = starter + datetime.timedelta(=+ints)
  return time

Answer 1 · 2015-08-14T00:36:04Z

August 14, 2015 12:36am

You have to create a time delta depending on the users input in the string. The string is going to contain the format of the int. Here's my solution, let me know If this helped you.

import datetime

starter = datetime.datetime(2015, 10, 21, 16, 29)

# Remember, you can't set "years" on a timedelta!
# Consider a year to be 365 days.

## Example
# time_machine(5, "minutes") => datetime(2015, 10, 21, 16, 34)


def time_machine(my_int, my_string):
    if my_string == "minutes":
        my_delta = datetime.timedelta(minutes = my_int)
    elif my_string == "days":
        my_delta = datetime.timedelta(days = my_int)
    elif my_string == "hours":
        my_delta = datetime.timedelta(hours = my_int)
    elif my_string == "years":
        my_delta = datetime.timedelta(days = my_int * 365)

    return starter + my_delta

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Stuck at datetime.datetime

1 Answer

Martin Cornejo Saavedra

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