Welcome to the Treehouse Community
Want to collaborate on code errors? Have bugs you need feedback on? Looking for an extra set of eyes on your latest project? Get support with fellow developers, designers, and programmers of all backgrounds and skill levels here with the Treehouse Community! While you're at it, check out some resources Treehouse students have shared here.
Looking to learn something new?
Treehouse offers a seven day free trial for new students. Get access to thousands of hours of content and join thousands of Treehouse students and alumni in the community today.
Start your free trialBruce McMinn
10,030 PointsSubqueries Review & Practice # 1 Clunky Answer
So question 1 asks for a list of all titles and a count of duplicate books. That sounds like a column of words and another column with a single numeric entry. Can I combine these two making a derived table of either?
-- a list of all books, no duplicate titles
SELECT bn.title FROM books_north AS bn
EXCEPT
SELECT bs.title FROM books_south AS bs
UNION
SELECT bs.title FROM books_south AS bs;
and
-- a complicated way to get the number 12
SELECT COUNT(*) AS BooksWithMultipleCopies FROM
(SELECT COUNT(*) as book_num
FROM (SELECT title FROM books_north
UNION ALL
SELECT title FROM books_south)
GROUP BY title
HAVING book_num>1);
I'm guessing that there isn't a good join criteria??
Bruce McMinn
10,030 PointsSure thing Steven, thanks for your help.
The link to the database is: https://teamtreehouse.com/sql_playgrounds/522#/queries/670ffc6e-68f8-4117-aeda-a3bd5d37d4b3
and it is at: Databases/Querying Relational Databases/Subqueries/Review and Practice.
Do you know how I get a question's subject that specific when I ask it? As in
Steven Parker
231,248 PointsSteven Parker
231,248 PointsActually it sounds like it could be done easily with a join. Could you share a link to the course page so the original instructions can be viewed?