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PHP PHP Arrays and Control Structures PHP Arrays Multidimensional Arrays

Zachary French
Zachary French
1,081 Points
Posted by Zachary French
Zachary French
1,081 Points

The quiz says I should not be modifying the output, but the question specifically asks me to. What am i doing wrong?

The output of my code shows the exact same output as the sample code that I was to replace. Not sure what I am doing wrong.

The sample code

echo"<li>Alena Holligan : alena.holligan@teamtreehouse.com/n"; echo"<li>Dave McFarlad: dave.mcfarland@teamtreehouse.com/n"; echo"<li>Treasure Porth : treasure.porth@teamtreehouse.com/n"; echo"<li>Alena Holligan : alena.holligan@teamtreehouse.com/n";

index.php 
<?php
//edit this array
$contacts = array(
    array(
        'name' => 'Alena Holligan',
        'email' => 'alena.holligan@teamtreehouse.com'), 
    array(
        'name' => 'Dave McFarland',
        'email' => 'dave.mcfarland@teamtreehouse.com'), 
    array(
        'name' => 'Treasure Porth',
        'email' => 'treasure.porth@teamtreehouse.com'), 
    array(
        'name' => 'Andrew Chalkley',
        'email' => 'andrew.chalkley@teamtreehouse.com')
  );

echo "<ul>\n";
//$contacts[0] will return 'Alena Holligan' in our simple array of names.
echo "<li>" . $contacts[0]['name'] . " : " . $contacts[0]['email'];
echo "<li>" . $contacts[1]['name'] . " : " . $contacts[1]['email'];
echo "<li>" . $contacts[2]['name'] . " : " . $contacts[2]['email'];
echo "<li>" . $contacts[3]['name'] . " : " . $contacts[3]['email'];
echo "</ul>\n";

1 Answer

Jason Anello
Jason Anello
Courses Plus Student 94,610 Points

Hi Zachary,

The original output had a closing li tag and a \n after the email address.

echo "<li>Alena Holligan : alena.holligan@teamtreehouse.com</li>\n";

You're missing that from your code.

Zachary French
Zachary French
1,081 Points
Zachary French
Zachary French
1,081 Points

Thanks for the help. I assumed since the output was the same those were unnecessary. Thanks!