Welcome to the Treehouse Community

Want to collaborate on code errors? Have bugs you need feedback on? Looking for an extra set of eyes on your latest project? Get support with fellow developers, designers, and programmers of all backgrounds and skill levels here with the Treehouse Community! While you're at it, check out some resources Treehouse students have shared here.

Looking to learn something new?

Treehouse offers a seven day free trial for new students. Get access to thousands of hours of content and join thousands of Treehouse students and alumni in the community today.

Start your free trial

Python Introducing Lists Build an Application Multidimensional Musical Groups

Posted by Michel Storms
Michel Storms
1,433 Points

This works but I can't continue??? # Your code here for group in musical_groups: print (", ".join (group[1:]))

Hi, this works, gives the correct output and is pretty concise but I can't continue the course... what am I doing wrong?

Your code here

for group in musical_groups: print (", ".join (group[1:]))

Thanks!

groups.py 
musical_groups = [
    ["Ad Rock", "MCA", "Mike D."],
    ["John Lennon", "Paul McCartney", "Ringo Starr", "George Harrison"],
    ["Salt", "Peppa", "Spinderella"],
    ["Rivers Cuomo", "Patrick Wilson", "Brian Bell", "Scott Shriner"],
    ["Chuck D.", "Flavor Flav", "Professor Griff", "Khari Winn", "DJ Lord"],
    ["Axl Rose", "Slash", "Duff McKagan", "Steven Adler"],
    ["Run", "DMC", "Jam Master Jay"],
]
# Your code here
for group in musical_groups:
    print (", ".join (group[1:]))

1 Answer

Michel Storms
Michel Storms
1,433 Points

Ok, it does work when I add the group name to my output, which is not really correct with the assignment:

"Here is a multi-dimensional list of musical groups. The first dimension is group, the second is group members. Can you loop through each group and output the members joined together with a ", " comma space as a separator, please?"

It asks to output the members, not the group + members...