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Jesse Garcia
440 PointsTo print out name I type in %s to print out my string but it says missing format argument
Thank you for the guidance.
// I have setup a java.io.Console object for you named console
String firstName = "Jesse";
console.printf("%s can code Java!");
1 Answer
Jennifer Nordell
Treehouse TeacherHi there! You're soooo close here. We use the %s to tell Java that we're going to insert a string stored in a variable here. But then, we have to say which variable to insert in that spot. Take a look:
console.printf("%s can code in Java!", firstName);
So this will use the printf method on the console class. Inside that we send a string with the %s (which we sometimes call a token) to tell it to insert the string value assigned to a variable in this spot. Then we use a comma and list the variable name that holds the string to be inserted. It's also important to note that your string was missing the word "in" which I have corrected here.
Hope this helps!
