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Python

Posted by Hina K.
Hina K.
4,806 Points

TypeError: number() takes 0 positional arguments but 1 was given

What is wrong with my code?

def number():
    answer = number + number
    print(number)

number(2)
number(3)
number(0)



I keep getting this error:

treehouse:~/workspace$ python Practice.py                                                                                                            
Traceback (most recent call last):                                                                                                                   
  File "/home/treehouse/workspace/Practice.py", line 5, in <module>                                                                                  
    number(2)                                                                                                                                        
TypeError: number() takes 0 positional arguments but 1 was given

1 Answer

jb30
jb30
44,806 Points 
def number():
    answer = number + number
    print(number)

In the line def number():, the function does not have any parameters. If you want your function to accept an argument, you could change the first line to be def number(number):. Then, in your third line, the value for your parameter number will be printed out.

If you want the line answer = number + number to have a visible effect on your program, you could change your third line to print(answer) to print out the value for number + number.

Hina K.
Hina K.
4,806 Points

Thank you!