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Michael Nanni
7,358 PointsTypeError: sequence item 0: expected str instance, list found?
Trying to understand what this error means. Does it mean it can't parse the 0th list into a string?
What am I missing to make it turn those group members into a string? I have a join method but maybe it's in the wrong place.
musical_groups = [
["Ad Rock", "MCA", "Mike D."],
["John Lennon", "Paul McCartney", "Ringo Starr", "George Harrison"],
["Salt", "Peppa", "Spinderella"],
["Rivers Cuomo", "Patrick Wilson", "Brian Bell", "Scott Shriner"],
["Chuck D.", "Flavor Flav", "Professor Griff", "Khari Winn", "DJ Lord"],
["Axl Rose", "Slash", "Duff McKagan", "Steven Adler"],
["Run", "DMC", "Jam Master Jay"],
]
# Your code here
group_members = ", ".join(musical_groups)
for group in musical_groups:
print(group_members)
1 Answer
Daniel Turato
Java Web Development Techdegree Graduate 30,124 PointsYou are taking out each group and turning it into a string meaning when you loop over group_members you are in fact looping over characters and not elements in lists. You need to do something like this:
for group in musical_groups:
print(", ".join(group))