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Python Django REST Framework RESTful Django Create a ListView with a POST

Posted by Vit Gor
Vit Gor
522 Points

Used the code from the lesson exactly but it still doesn't work

I'm raging here. I've reread it about ten times in search of a mistake, compared it to code from previous lesson, to no avail. It's the same, with CourseSerializer renamed GameSerializer. And it doesn't work. I'm really close to flipping my shit here

scorekeeper/views.py 
from rest_framework.response import Response
from rest_framework.views import APIView

from . import models
from . import serializers


class GameListCreate(APIView):
    def get(self, request, format=None):
        games = models.Game.objects.all()
        serializer = serializers.GameSerializer(games, many=True)
        return Response(serializer.data)

    def post(self, request, format=None):
        serializer = serializers.GameSerializer(data=request.data)
        serializer.is_valid(raise_exception=True)
        serializer.save()
        return Response(serializer.data, status=status.HTTP_201_CREATED)

1 Answer

Dave StSomeWhere
Dave StSomeWhere
19,870 Points
Dave StSomeWhere
Dave StSomeWhere
19,870 Points

Just change your status value and it will pass:

# your line
 return Response(serializer.data, status=status.HTTP_201_CREATED)
# just set status to 201
 return Response(serializer.data, status=201)