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Java Java Basics Getting Started with Java Strings, Variables, and Formatting

foxtails
foxtails
3,655 Points
Posted by foxtails
foxtails
3,655 Points

variable %s... what is wrong here?

I really am not sure, where the problem is as in preview this looks correct if only ugly as I haven't put line divider/n.

Name.java 
// I have setup a java.io.Console object for you named console
String firstName = "Anna";
console.printf ("Anna can code in Java!");
console.printf ("%s can code in Java!", firstName);

1 Answer

Alexander Davison
Alexander Davison
65,469 Points
Alexander Davison
Alexander Davison
65,469 Points

Try getting rid of this line:

console.printf ("Anna can code in Java!");

The code challenge is only expect one print :)

Good luck! ~alex

foxtails
foxtails
3,655 Points
foxtails
foxtails
3,655 Points

Did it. Still doesn't go through.

Alexander Davison
Alexander Davison
65,469 Points

Maybe replacing the ! with a period would work :)