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George Graves
64 PointsVariables: What's wrong with this?
console.printf("%s, can write Java", firstName);
// I have setup a java.io.Console object for you named console
String firstName = "George";
console.printf("%s, can code in Java\n", firstName);
2 Answers
srikarvedantam
8,369 PointsWell, you are printing an extraneous ',' after "firstName" and '\n' at the end of the message. Also, you are missing '!' at the end of the message you are printing.
Stick to the instructions of the challenge presented as it is machine that's evaluating your code / output, rather than human who can be considerate. Here's a solution:
String firstName = "Srikar";
console.printf("%s can code in Java!", firstName);
Matthew Hardy
4,063 PointsDeleting the first comma in your second line of code, the one located after the %s, worked for me