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markhsia
2,139 PointsWhat does the "not a statement" error mean when compiling your java code mean?
When you compile code in java, and you have an error, it show you the error. One of the errors is "not a statement".
String firstName = console.readLine ("What is your first name?") ;
String lastName = console.readLine ("What is your last name?");
console.printf = ("First name %s"); firstName;
//The console.printf part has the error on it.
3 Answers
Shadd Anderson
Treehouse Project ReviewerWhen forming a printf statement, the format is ("sentence with placeholders",objects to replace placeholders);
In other words, instead of closing the parentheses and separating "firstName" with a semicolon, simply place a comma after the quotes, then put firstName, and then close the parentheses.
console.printf("First name: %s",firstName);
Jason Anders
Treehouse Moderator 145,860 PointsHey Christina,
There are a few things wrong with the printf line:
console.printfis a method and cannot have an equal sign. As you have it, it's trying to assign the string as a variable to the method, which can't be done.The
firstNamevariable needs to be inside of the parenthesis in order for it to be attached to the placeholder.You have a semi-colon where a comma should be.
Below is the correct line of code for you to review. I hope it makes sense. :)
console.printf("First name: %s", firstName);
Keep Coding!
Philip Gales
15,193 Pointsline 3 you used firstName;. This not a statement even though it is well-dressed. Below is the code you need for the challenge, make sure you understand line 3 as I have fixed it. I assume you placed the firstName outside of the last closing parenthesis because it told you (when you use console.printf = (); it will not let you use the formatted %s properly and will show random errors).
String firstName = console.readLine ("What is your first name?") ;
String lastName = console.readLine ("What is your last name?");
console.printf("First name: %s", firstName);
console.printf("Last name: %s", lastName);