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michellewong5
5,727 PointsWhat's missing for this minutes.py code challenge?
I tried to take 2 time snapshots of "now" at a and b. Since there wasn't much change in minutes, I added 5 minutes to b just to see num_minutes would return a nonzero value. I took the time_delta of b-a in seconds -> converted to minutes by dividing by 60 -> and rounded using "round".
import datetime
def minutes():
a = datetime.datetime.now()
b = datetime.datetime.now() + datetime.timedelta(minutes=5)
timedelta = b-a
num_minutes = round(timedelta.total_seconds() / 60)
return num_minutes
2 Answers
Mel Rumsey
Treehouse ModeratorHey michellewong5 you are not too far off here
What we want to do is create a function with 2 arguments that will be datetimes. We can just call them a and b accordingly.
def minutes(a, b):
Then we want to subtract the smaller number from the larger as you have done it.
timedelta = b-a
then we can return the rounded timedelta.total_seconds()/60.
Great job on what you have done so far, there were just a few small things that needed to be changed. :) Keep up the great work and let us know if we can assist you further!
michellewong5
5,727 PointsOk, got it. Thank you Mel.