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Start your free trialkeith rezendes
4,459 PointsWhat's up with the challenges lately, nothing seems to work and the error messages don't help.
See my code and more importantly, the error message, don't change string, I didn't even touch it.
import re
string = '1234567890'
good_numbers = re.findall(r'[^567]', string)
1 Answer
Tony Christopher
3,756 PointsThe problem is you're checking each character to see if it's a '5', '6' or '7' and then returning the character. If you run that in Python you'll see that the response is ['1', '2', '3', '4', '8', '9', '0']
, which is not what is wanted. It should return ['1234', '890']
. To get that you need to match groups of at least 1 character that isn't a '5', '6' or '7'. The correct solution is
good_numbers = re.findall(r"[^567]+", string)