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Python

Asher Orr
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Asher Orr
Python Development Techdegree Graduate 9,408 Points
Posted by Asher Orr
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Asher Orr
Python Development Techdegree Graduate 9,408 Points

When updating a dictionary using a for loop, all keys return the same value (despite iterating through multiple values.)

Hi everyone!

I created a function called splitsville. It takes 1 parameter, an address ('100 E Main St, Anywhereville, Oregon, 22222'.)

I split the string into the street, city, state, and zip code.

Now, I'm trying to return a dictionary with the keys:

  • street
  • city
  • state
  • zip_code

... and the corresponding values from the split string. For example: {'street': '100 E Main St', 'city': 'Anywhereville', etc.}

I wrote this code:

def splitsville(address):
    address_values = address.split(", ")
    dictionary = {}
    for value in address_values:
        dictionary.update({"street" : value})
        dictionary.update({"city" : value})
        dictionary.update({"state" : value})
        dictionary.update({"zip_code" : value})
    print(dictionary)

splitsville("100 E Main Street, Anywhereville, Oregon, 22222")

However, only the last value in address_values is associated with each key. My console prints out:

{'street': '22222', 'city': '22222', 'state': '22222', 'zip': '22222'}

Any ideas on why this is happening?

Thank you all so much!

1 Answer

Mark Sebeck
MOD
Mark Sebeck
Treehouse Moderator 37,777 Points
Mark Sebeck
Mark Sebeck
Treehouse Moderator 37,777 Points

Hi Asher. I'll tell you why it's happening and let you work on the fix. So remember the "value" in your for loop will only increment once for each iteration of your loop. So the first time all dictionary keys will equal "100 E Main Street" and the second time all keys will equal "Anywhereville" and so on until the last time everything will equal "22222". To help see this move your print inside the loop. You only want to set one key each time through the loop.

Hope this helps Asher and good luck!

Asher Orr
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.a{fill-rule:evenodd;}techdegree seal-36
Asher Orr
Python Development Techdegree Graduate 9,408 Points
Asher Orr
.a{fill-rule:evenodd;}techdegree seal-36
Asher Orr
Python Development Techdegree Graduate 9,408 Points

Hey Mark, thanks for your feedback! It's very helpful.

If I understand correctly, setting only one key per loop would mean creating multiple loops. That seemed a little messy to me, so I went with this solution:

def splitsville(address):
    address_values = address.split(", ")
    dictionary = {}
    dictionary.update({"street" : address_values[0]})
    address_values.pop(0)
    dictionary.update({"city": address_values[0]})
    address_values.pop(0)
    dictionary.update({"state": address_values[0]})
    address_values.pop(0)
    dictionary.update({"zip_code": address_values[0]})
    print(dictionary)


splitsville("100 E Main Street, Anywhereville, Oregon, 22222")

It works, too! This prints to the console:

{'street': '100 E Main Street', 'city': 'Anywhereville', 'state': 'Oregon', 'zip_code': '22222'}

Again, thank you for taking the time to answer my question. I appreciate you!

Mark Sebeck
Mark Sebeck
Treehouse Moderator 37,777 Points
Mark Sebeck
Mark Sebeck
Treehouse Moderator 37,777 Points

Great job Asher getting it to work. Thanks for setting the Best answer. It's nice so that others know you have an answer and don't click on it to see if you need help. Also thanks for the update with your solution. Keep at it and good luck!