Welcome to the Treehouse Community
Want to collaborate on code errors? Have bugs you need feedback on? Looking for an extra set of eyes on your latest project? Get support with fellow developers, designers, and programmers of all backgrounds and skill levels here with the Treehouse Community! While you're at it, check out some resources Treehouse students have shared here.
Looking to learn something new?
Treehouse offers a seven day free trial for new students. Get access to thousands of hours of content and join thousands of Treehouse students and alumni in the community today.
Start your free trialSudhir Raghur Venkatesalu
7,347 PointsWhere do i go wrong ?
def combiner(*args): a = "" b = 0
for i in list(args):
if isinstance(i,str):
a += i
print(a)
elif isinstance(i,int) or isinstance(i,float):
print('{} i in int - '.format(i))
b += i
print(b)
result = "{}{}".format(a, b)
return result
r = combiner("apple",5.8,"dog",8) print(r)
def combiner(*args):
a = ""
b = 0
for i in list(args):
if isinstance(i,str):
a += i
print(a)
elif isinstance(i,int) or isinstance(i,float):
print('{} i in int - '.format(i))
b += i
print(b)
result = "{}{}".format(a, b)
return result
r = combiner("apple",5.8,"dog",8)
print(r)
1 Answer
Steven Parker
231,248 PointsThe instructions say the function will take "a single argument, which will be a list made up of strings and numbers".
Since there will only be one argument and it will already be a list, you don't need the "splat" (packing operator) in the definition (or the "list" function around the iterable).
Sudhir Raghur Venkatesalu
7,347 PointsSudhir Raghur Venkatesalu
7,347 PointsI did try removing the split, still its throwing error. Though It gives me the answer when I try in the terminal.
Steven Parker
231,248 PointsSteven Parker
231,248 PointsAlso, for the challenge you only need to define the function. You don't need to call it, create the variable "r", or "print" anything.