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Databases

Ido Galili
Ido Galili
1,160 Points
Posted by Ido Galili
Ido Galili
1,160 Points

Why do I recieve wrong answer if the results ar correct?

I wrote the correct quiry and keep recieving wrong answer. i counted the models and the result matches the data, I cant figure whats the problem.

Stuart Wright
Stuart Wright
41,120 Points
Stuart Wright
Stuart Wright
41,120 Points

Can you post a link to the challenge and also include your code so we can check it please?

Ido Galili
Ido Galili
1,160 Points
Ido Galili
Ido Galili
1,160 Points

Thanks! Link: https://teamtreehouse.com/library/querying-relational-databases/subqueries/subqueries

Code: SELECT Model.ModelID, Model.ModelName, Car.StickerPrice FROM Model LEFT OUTER JOIN Car ON Model.ModelID = Car.ModelID WHERE Car.StickerPrice IN (SELECT Car.StickerPrice FROM Car WHERE Car.StickerPrice >= 30000);

3 Answers

Umesh Ravji
Umesh Ravji
42,386 Points
Umesh Ravji
Umesh Ravji
42,386 Points

Hi Ido

Bummer! The subquery doesn't return all ModelIDs for cars with the sticker price greater than 30000.

SELECT Car.StickerPrice FROM Car WHERE Car.StickerPrice >= 30000

Your subquery needs to return the ModelIDs, not the StickerPrice.

Also make sure you are selecting the correct columns in your query, you only need to select ModelName, and there's no need to perform a join in this question.

Stuart Wright
Stuart Wright
41,120 Points
Stuart Wright
Stuart Wright
41,120 Points

You don't actually need to use a JOIN here, because the subquery does everything you need it to:

SELECT ModelName FROM Model 
WHERE ModelID IN 
    (SELECT ModelID FROM Car WHERE StickerPrice > 30000);

The code you posted will return duplicate values for model names because of the join, whereas the above code returns a list of unique model names.

Ido Galili
Ido Galili
1,160 Points
Ido Galili
Ido Galili
1,160 Points

Thanks guys, Stuart I tried what you wrote but chose StickerPrice instead of ModelID.

Thanks for the important lesson.