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Python

Jack Cummins
Jack Cummins
17,417 Points
Posted by Jack Cummins
Jack Cummins
17,417 Points

Why is my code not passing?

The instructions are: Great! Let's make one more scoring method! Create a score_yatzy method. If there are five dice with the same value, return 50. Otherwise, return 0.

scoresheets.py 
class YatzyScoresheet:
    def score_ones(self, hand):
        return sum(hand.ones)

    def _score_set(self, hand, set_size):
        scores = [0]
        for worth, count in hand._sets.items():
            if count == set_size:
                scores.append(worth*set_size)
        return max(scores)

    def score_one_pair(self, hand):
        return self._score_set(hand, 2)

    def score_chance(self, hand):
        return sum(hand)
    def score_yatzy(self, hand):
        check_value = hand[0]
        check_hand = []
        for die in hand:
            if die == check_value:
                check_hand.append(die)

        if len(check_hand) == 5:
            return 50
        else:
            return 0
gsav
gsav
3,800 Points

little unsure why your code isn't working, but a much easier way is to convert to set and check set length.

def score_yatzy(self, hand):
        if len(set(hand)) == 1:
            return 50
        else:
            return 0

3 Answers

Steven Parker
Steven Parker
231,248 Points
Steven Parker
Steven Parker
231,248 Points

This looks OK to me. So I tried pasting it directly into the challenge and it passed both tasks!

Try again?

Ross Coe
Ross Coe
5,061 Points
Ross Coe
Ross Coe
5,061 Points

@gsav - that's a very neat solution, well done

Marcos Lisboa
Marcos Lisboa
8,117 Points
Marcos Lisboa
Marcos Lisboa
8,117 Points

The question with this solution is:

What if the first element in the list is not the one repeated 5 times? Example:

[1, 4, 4, 4, 4, 4]

I think gsav solution is the best, but with a little rectification:

def score_yatzy(self, hand):
        if len(set(hand)) == 1 or len(set(hand)) == 2:
            return 50
        else:
            return 0