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Python Django Class-based Views Classy Views Basic View

Zhijie Huang
PLUS
Zhijie Huang
Courses Plus Student 86 Points
Posted by Zhijie Huang
Zhijie Huang
Courses Plus Student 86 Points

Why is the url I wrote not working

it always say cannot find an url for my views what, did I do wrong?

myproject/urls.py 
from django.conf.urls import url, include

from . import views

urlpatterns = [
    url(r'.', views.WelcomeView.as_view(), name='hello'),
]
myproject/views.py 
from django.views.generic import View
from django.http import HttpResponse


class WelcomeView(View):
    def get(self, request):
        return HttpResponse ("Beautiful")
Erika Suzuki
Erika Suzuki
20,299 Points
Erika Suzuki
Erika Suzuki
20,299 Points

I notice you only have a '.' (dot) on your regex pattern. What URL format did you want to match to?

1 Answer

Chris Freeman
MOD
Chris Freeman
Treehouse Moderator 68,441 Points
Chris Freeman
Chris Freeman
Treehouse Moderator 68,441 Points

You are very close! The url regex route that represents '/' is r'^$'