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Start your free trialNOIR TRADI
374 Pointswhy second output is NONE? def add_two(num): val = num + 2 print(val) print (add_two(10))
tell me please why first output is 10(right) and second is NONE?
def add_two(num): val = num + 2 print(val)
print (add_two(10))
6 Answers
KRIS NIKOLAISEN
54,971 PointsWhen a function doesn't have a return statement the default return value is None. The following will print 12 in both cases.
def add_two(num):
val = num + 2
print(val)
return val
print(add_two(10))
Josh Keenan
20,315 PointsCan you tell me what the second input is?
NOIR TRADI
374 Pointsprint(add_two(10))
Ary de Oliveira
28,298 Points# ====> in global scope.
# ====> When a function doesn't have a return
# statement the default return value is None.
def print_name():
print('Ary de Oliveira')
def print_favorite_name():
print('Ary')
numero = 120
def set_numero():
numero = 60
key = 'a'
print(key)
print(set_numero())
print(numero)
print_name()
print_favorite_name()
my_var = 10
def multiply():
my_var = 10 * 2
print(my_var)
#ary
Ben Bassler
1,806 PointsPlease tell me what you passed in as an argument for add_two() when it outputted 'None'.
NOIR TRADI
374 Pointsprint(add_two(10))
KRIS NIKOLAISEN
54,971 PointsThis has already been answered. Your add_two() function returns None because it has no explicit return statement. As a result print(add_two(10)) displays None.
NOIR TRADI
374 Pointsthanks guys!!
NOIR TRADI
374 PointsNOIR TRADI
374 Pointsdef add_two(num): val = num + 2 print(val)
print (add_two(10))
RESULT IS...
treehouse:~/workspace$ python functions.py
12
None
why None???