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Python Python Basics Functions and Looping Exception Flow

Pritam Pal
Pritam Pal
1,203 Points
Posted by Pritam Pal
Pritam Pal
1,203 Points

why the else part is coming in the output in this example. please help me

print("A") try: result = "test" + 5 print("B") except ValueError: print("C") except TypeError: print("D") else: print("E") print("F")

1 Answer

KRIS NIKOLAISEN
KRIS NIKOLAISEN
54,971 Points
KRIS NIKOLAISEN
KRIS NIKOLAISEN
54,971 Points 
print("A")
try:
    result = "test" + 5
    print("B")
except ValueError:
    print("C")
except TypeError:
    print("D")
else:
    print("E")
print("F")

The else is not printed in this example. "test" + 5 results in a type error for attempting to add a string to an integer. This is handled by except TypeError so D is printed and else is skipped.

Pritam Pal
Pritam Pal
1,203 Points
Pritam Pal
Pritam Pal
1,203 Points

Thank you for helping me out. It means a lot