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Python Comparison Solution

Posted by Kabelo Mayisa
.a{fill-rule:evenodd;}techdegree
Kabelo Mayisa
Full Stack JavaScript Techdegree Student 2,556 Points

Wow, I totally did it differently, is it wrong?

My solution works perfectly but it is totally different to how Ken solved it, is this a wrong thing? Heres my code:

fizzbuzz.py 
#if devisible by both 3 and 5
if user_number % 3 == 0 and user_number % 5 == 0:
    print('is a FizzBuzz number ...')

#if divisible by 3
elif user_number % 3 == 0 : 
    print('is a Fizz number...')
#if divisible by 5    
elif user_number % 5 == 0:
    print('is a Buzz number...')
#if it is either divisible by 3 or 5
else:
    print('is neither a fizzy or a buzzy number ...')

2 Answers

Mark Tripney
Mark Tripney
6,009 Points
Mark Tripney
Mark Tripney
6,009 Points

The difference, Kabelo, is that you haven't assigned is_fizz and is_buzz to Boolean values, as requested in the TODO. Both methods - Ken's and yours - produce the same results, however!

Myers Carpenter
Myers Carpenter
6,421 Points
Myers Carpenter
Myers Carpenter
6,421 Points

Looks fine to me. Ken's answer just moved the comparisons before the if block.